Find the number of CORRECT order against ment | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $(i)$ $D_2O$ ($2 	imes 1 + 8 = 10$ electrons) and $H_2O$ ($2 	imes 1 + 8 = 10$ electrons). So,$D_2O = H_2O$ is $CORRECT$.$(ii)$ The enthalpy of

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(B) $(i)$ $D_2O$ ($2 	imes 1 + 8 = 10$ electrons) and $H_2O$ ($2 	imes 1 + 8 = 10$ electrons). So,$D_2O = H_2O$ is $CORRECT$.$(ii)$ The enthalpy of formation $|\Delta H_f|$ for $D_2O$ is higher than $H_2O$ due to stronger $O-D$ bonds compared to $O-H$ bonds. So,$D_2O > H_2O$ is $CORRECT$.$(iii)$ The enthalpy of vaporization $|\Delta H_{vaporization}|$ for $D_2O$ is higher than $H_2O$ due to stronger intermolecular hydrogen bonding in $D_2O$. So,$D_2O > H_2O$ is $CORRECT$.$(iv)$ The density of $D_2O$ $(1.107 \ g/mL)$ is higher than $H_2O$ $(1.000 \ g/mL)$. So,$D_2O > H_2O$ is $CORRECT$.$(v)$ Molecular mass of $D_2O$ $(20 \ u)$ is higher than $H_2O$ $(18 \ u)$. So,$D_2O > H_2O$ is $CORRECT$.All $5$ statements are $CORRECT$.

Find the number of $CORRECT$ order against mentioned property :-
$(i)$ $D_2O = H_2O$ (number of electrons)
$(ii)$ $D_2O > H_2O$ $(|\Delta H_f|)$
$(iii)$ $D_2O > H_2O$ $(|\Delta H_{vaporization}|)$
$(iv)$ $D_2O > H_2O$ (density)
$(v)$ $D_2O > H_2O$ (Molecular mass)

Similar Questions

Permanent hardness in water is due to the presence of which of the following ions?

Calgon is used for water treatment. Which of the following statements is $NOT$ true about Calgon?

Which of the following is the best scientific method to test the presence of water in a liquid?

How can saline hydrides remove traces of water from organic compounds?

Which of the following will determine whether the given colourless liquid is water or not?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Find the number of $CORRECT$ order against mentioned property :-$(i)$ $D_2O = H_2O$ (number of electrons)$(ii)$ $D_2O > H_2O$ $(|\Delta H_f|)$$(iii)$ $D_2O > H_2O$ $(|\Delta H_{vaporization}|)$$(iv)$ $D_2O > H_2O$ (density)$(v)$ $D_2O > H_2O$ (Molecular mass)